Practicing Success
Practicing Success
CUET Preparation Today
If energy E, velocity v and time T are chosen as fundamental units, the dimensions of surface tension will be: |
$[Ev^{–2}T^{–2}]$ $[Ev^{–1}T^{–2}]$ $[Ev^2T^{–1}]$ $[E^2v^{–1}T^{–1}]$ |
$[Ev^{–2}T^{–2}]$ |
The correct answer is Option (1) → $[Ev^{–2}T^{–2}]$ $Surface\, tension = \frac{force}{length}$ $=\frac{energy}{length × length}=\frac{energy}{(speed \times time)^2}$ $=EV^{–2}T^{–2}$ |
