Practicing Success
The integrated rate equation for a first-order reaction is \(\frac{kt}{2.303} = logR_o – logR_t\). The straight line graph is obtained by plotting: |
time vs \(R_t\) time vs \(log R_t\) time vs \(\frac{1}{R_t}\) time vs\(R_o\) |
time vs \(log R_t\) |
We have the integrated rate equation for a first-order reaction:
\(log R_t = -\frac{k}{2.303}t + log R_o\) This equation is comparable to equation of a straight line \((y = mx + c)\).When a graph is plotted between \(log R_t \)and time \(t\) at different intervals of time we get a straight line. |