CUET Preparation Today
Dimensional formula of Planck constant is: |
$[ML^2T^3]$ $[M^0L^0T^0]$ $[ML^3T^2]$ $[ML^2T^{-1}]$ |
$[ML^2T^{-1}]$ |
$ p = \frac{h}{\lambda}$ $ h = p\lambda $ Dimension of h is $[ML^2T^{-1}]$ The correct answer is Option (4) → $[ML^2T^{-1}]$ |
