Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

If the frequency required for the transition from 2nd to 5th orbit is 4 x \( { 10}^{ 15} \) Hz, what will the corresponding energy be?

Options:

26.5 eV

16.5 eV

26.5 J

16.5 J

Correct Answer:

16.5 eV

Explanation:

energy : E = hv

v = 4 x \( { 10}^{ 15} \) Hz

$ E = 6.63\times 10^{-34}\times 4\times 10^{15} J = 16.5 eV$