If the order and degree of the differential equation \(\sqrt {\frac{d^2y}{dx^2}}\) =\((1+\frac{dy}{dx})^{\frac{1}{3}}\) are a and b respectively, then the value of a2 + b2 is
Answer & explanation
Correct answer: option 4
\(\sqrt {\frac{d^2y}{dx^2}}=(1+\frac{dy}{dx})^{\frac{1}{3}}=(\frac{d^2y}{dx^2})^3=(1+\frac{dy}{dx})^2\)
= order = 2 = a
degree = 3 = b
$∴ a^2 + b^2 = 2^2 + 3^2 = 4 + 9 = 13$
Option D is correct.