An electron, an $\alpha$ particle, a proton and a deutron have the same kinetic energy. Which of these particles has the shortest De Broglie wavelength.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\alpha$ Particle
Using De-Broglie,
$λ=\frac{h}{P}=\frac{h}{\sqrt{2mk}}$
$⇒λ∝\frac{1}{\sqrt{m}}$
and, the $\alpha$-Particle has greatest mass ⇒ Shortest wavelength.