A solid metallic hemisphere of radius 6.3 cm is melted and recast into a right circular cylinder of radius 9 cm. What is the height (in cm, correct to one decimal place) of the cylinder?

2.1

We know that,

Volume of cylinder = πr²h

Given that,

Radius of hemisphere = 6.3 cm

Radius of cylinder = 9 cm

Volume of hemisphere = \(\frac{2}{3}\)× πr³= \(\frac{2}{3}\)× π × (6.3)³

Volume of cylinder = πh × (9)²

Then,

= \(\frac{2}{3}\)× π × 6.3³ = πh × 9²

= h = 2.058 = 2.1