A solid metallic hemisphere of radius 6.3 cm is melted and recast into a right circular cylinder of radius 9 cm. What is the height (in cm, correct to one decimal place) of the cylinder?
Answer & explanation
Correct answer: option 4
We know that,
Volume of cylinder = πr2h
Given that,
Radius of hemisphere = 6.3 cm
Radius of cylinder = 9 cm
Volume of hemisphere = \(\frac{2}{3}\)× πr3= \(\frac{2}{3}\)× π × (6.3)3
Volume of cylinder = πh × (9)2
Then,
= \(\frac{2}{3}\)× π × 6.33 = πh × 92
= h = 2.058 = 2.1