Target Exam

CUET

Subject

Chemistry

Chapter

Organic: Aldehydes, Ketones and Carboxylic Acids

Question:

Read the following passage given below and answer the question.

Andehydes and ketones undergo nucleophilic addition reactions. A nucleophile attacks the electrophilic carbon atom of polar carbonyl group from perpendicular to plane of \(sp^2\) hybridized orbitals of carbonyl carbon. The hybridization of carbon changes from \(sp^2\) \(sp^3\) and a tetrahedral alkoxide intermediate is formed. This captures \(H^+\) to give neutral product. In carboxylic acids, carbonyl carbon is less electrophilic than carbonyl carbon carbon of aldehydes and ketones.

The optimum pH for carrying out the reaction of aldehyde with hydroxylamine to form oxime is

Options:

pH = 1

pH = 4 - 5

pH = 12

Any pH

Correct Answer:

pH = 4 - 5

Explanation:

The correct answer is option 2. pH = 4 - 5.

Let us delve into the reaction of aldehydes with hydroxylamine to form oximes and understand why a mildly acidic pH is optimal for this process.

Reaction

In this reaction, an aldehyde (R-CHO) reacts with hydroxylamine (\( \text{NH}_2\text{OH} \)) to produce an oxime (\( \text{R-CH=NOH} \)) and water.

The aldehyde (\( \text{R-CHO} \)) can be protonated in acidic conditions. The protonation of the carbonyl oxygen increases the electrophilicity of the carbonyl carbon, making it more susceptible to nucleophilic attack. Hydroxylamine (\( \text{NH}_2\text{OH} \)) acts as a nucleophile and attacks the electrophilic carbonyl carbon to form a hemiactal intermediate. The hemiactal intermediate then reacts with another molecule of hydroxylamine, which leads to the formation of the oxime. In the acidic medium, the protonated hydroxylamine facilitates the reaction, and water is removed as a byproduct.

Why Mildly Acidic Conditions Are Optimal

Enhanced Electrophilicity: Under mildly acidic conditions (pH 4-5), the carbonyl carbon of the aldehyde is more electrophilic due to protonation of the carbonyl oxygen. This makes the carbonyl carbon more susceptible to nucleophilic attack by hydroxylamine.

Stabilization of Intermediates: The acid catalyzes the formation of the oxime by stabilizing the intermediate species. Acidic conditions also help in preventing side reactions and degradation of hydroxylamine.

Avoiding Side Reactions:If the pH is too low (e.g., pH = 1), the environment might be overly acidic, which could lead to side reactions, such as hydrolysis of the oxime or degradation of hydroxylamine. Conversely, if the pH is too high (e.g., pH = 12), the reaction might be adversely affected, as strong bases could hydrolyze the oxime or affect the stability of hydroxylamine.

Reaction Efficiency: At a pH of around 4-5, the reaction proceeds efficiently without the risk of unwanted side reactions or instability of reactants and products.

Summary

The optimal pH for the reaction of aldehydes with hydroxylamine to form oximes is 4-5. This mildly acidic pH provides the right balance to enhance the electrophilicity of the aldehyde carbonyl carbon, stabilize intermediates, and avoid issues associated with very low or very high pH conditions.