The equation of the plane parallel to the plane 4x – 3y + 2z + 1 = 0 and passing through the point (5, 1, – 6) is :

4x − 3y + 2z − 5 = 0

Equation of the plane parallel to the plane 4x − 3y + 2z + 1 = 0 is of the form of

4x – 3y + 2z + k = 0 again it passes through (5, 1, − 6)

so, 20 − 3 − 12 + k = 0 ⇒ k = − 5

Therefore required equation is 4x − 3y + 2z − 5 = 0.