Find the mean proportion of \(\frac{1}{3

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Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

Find the mean proportion of \(\frac{1}{36}\) and \(\frac{1}{16}\) .

Options:

\(\frac{1}{6 }\)

\(\frac{1}{ 4}\)

\(\frac{1}{24}\)

\(\frac{1}{25}\)

Correct Answer:

\(\frac{1}{24}\)

Explanation:

Mean proportion of a and b = \(\sqrt {a × b }\)

⇒ Mean proportion = \(\sqrt {\frac{1}{36} × \frac{1}{16}}\)

= \(\frac{1}{6 × 4}\) = \(\frac{1}{24}\)