Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

$\frac{\cos 20^{\circ}}{\sin 70^{\circ}}+\frac{\cos \theta}{\sin \left(90^{\circ}-\theta\right)}=$ _________ .

Options:

-2

$\frac{1}{2}$

$-\frac{1}{2}$

2

Correct Answer:

2

Explanation:

\(\frac{cos20°}{sin70°}\) + \(\frac{cosθ}{sin( 90° -θ ) }\) 

We know , sinA = cos( 90° - A )

= \(\frac{cos20°}{cos( 90° - 70° )}\) + \(\frac{cosθ}{cos θ }\) 

= \(\frac{cos20°}{cos20° }\)  + 1

= 1 + 1

= 2