The area of a quadrant of a circle is $\frac{\pi}{9} m^2$. Its radius (in metres) is equal to:
Answer & explanation
Correct answer: option 1
We know that,
The area of a quadrant of a circle is equal to one-fourth of the area of the circle = \(\frac{πr^2}{4}\)
Area of a quadrant of a circle is = $\frac{\pi}{9} m^2$
So,
\(\frac{πr^2}{4}\) = \(\frac{π}{9}\)
= r2 = \(\frac{4}{9}\)
= r = \(\frac{2}{3}\)
$\frac{\pi}{9} m^2$