CUET Preparation Today
The distribution of the electric field due to charges A and B is shown in figure. The correct statement is:
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A is positive, B is negative and |A| > |B| A is positive, B is negative and |A| < |B| Both are positive and |A| < |B| Both are negative and |A| < |B| |
A is positive, B is negative and |A| < |B| |
The correct answer is Option (2) → A is positive, B is negative and |A| < |B|
A is positive because the electric field lines start from positive and end at negative charge. (⇒ B is negative) Also, $|A|<|B|$ because the number of field lines at B is greater then as compared to A. |
