If $ K = \frac{1}{K} + 2 = 0 $ and K <

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Home Questions U4B384357X

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If $ K = \frac{1}{K} + 2 = 0 $ and K < 0, then what is the value of $K^{17}+\frac{1}{K^{11}}$?

Options:

-17

-2

-1

Correct Answer:

-2

Explanation:

If $ K = \frac{1}{K} + 2 = 0 $

$ K = \frac{1}{K} = -2 $

Put k = -1

$K^{17}+\frac{1}{K^{11}}$ = $1^{17}+\frac{1}{1^{11}}$ = -2