When the electron in hydrogen atom jumps from the 2nd orbit to the 1st orbit, the wavelength of the radiation emitted is λ. When the electron jumps from the 3rd orbit to 1st orbit, the wavelength of emitted radiation is:

$\frac{27}{32}λ$ $\frac{27}{5}λ$ $\frac{4}{5}λ$ $\frac{2}{3}λ$

$\frac{27}{32}λ$

The correct answer is Option (1) → $\frac{27}{32}λ$