A speaks the truth in 70% cases and B speaks the truth in 80% cases. The probability that they will contradict each other in describing a single event is

0.38 0.56 0.62 0.94

0.38

$P(A)=\frac{7}{10}, P(B)=\frac{8}{10}$ $P(C)=\frac{7}{10}\left(1-\frac{8}{10}\right)+\left(1-\frac{7}{10}\right) \frac{8}{10}=\frac{14}{100}+\frac{24}{100}=\frac{38}{100}=0.38$