Find the value of \(\alpha \) if \((\cot {\alpha } - 2) I = I\)
Answer & explanation
Correct answer: option 3
\((\cot {\alpha } - 2) I = I\)
\((\cot {\alpha } - 2)\begin{bmatrix}
1 & 0\\ 0 & 1\end{bmatrix}= \begin{bmatrix}
1 & 0\\ 0 & 1\end{bmatrix}\)
\(\begin{bmatrix} -2+cot{\alpha}& 0\\ 0 & +2+cot{\alpha} \end{bmatrix}=\begin{bmatrix}
1 & 0\\ 0 & 1\end{bmatrix}\)
By equating the elements component-wise we get
\(\cot {\alpha }- 2 = 1\) \(\cot{\alpha } = 1\)
So, \(\alpha \) = \(\frac{\Pi }{4}\) or \(\frac{5\Pi }{4}\)