If the concentration of a reactant is reduced to half, the rate of reaction becomes 1/4. What will be the order of reaction?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 2
Rate law:
$\text{Rate} \propto [A]^n$
When concentration is reduced to half:
$\left(\frac{1}{2}\right)^n = \frac{1}{4}$
$\left(\frac{1}{2}\right)^n = \left(\frac{1}{2}\right)^2$
So,
$n = 2$