CUET Preparation Today
A pure inductor of 70 mH is connected to a source of 220 V. The frequency of the source is 50 Hz. The current in the circuit is |
10.0 A 3.15 A 4.4 A 5 A |
10.0 A |
The correct answer is Option (1) → 10.0 A The inductive reactance ($X_L$) is, $X_L=2\pi VL$ $=2\pi(50)(70×10^{-3})$ $≃21.99Ω$ Using Ohm's law, $I=\frac{V}{X_L}=\frac{220}{21.99}≃10.0A$ |
