A pure inductor of 70 mH is connected to a source of 220 V. The frequency of the source is 50 Hz. The current in the circuit is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 10.0 A
The inductive reactance ($X_L$) is,
$X_L=2\pi VL$
$=2\pi(50)(70×10^{-3})$
$≃21.99Ω$
Using Ohm's law,
$I=\frac{V}{X_L}=\frac{220}{21.99}≃10.0A$