There are 6 cards numbered 1 to 6 , one number on one card. Two cards are drawn at random without replacement. Let X denote the sum of the numbers on the two cards drawn. Then P(X > 3) is:

$\frac{14}{15}$ $\frac{1}{15}$ $\frac{11}{12}$ $\frac{1}{12}$

$\frac{14}{15}$

The correct answer is Option (1) → $\frac{14}{15}$