The inner circumference of a circular path enclosed between two concentric circles is 264 m. The uniform width of the circular path is 3 m. What is the area (in m2, to the nearest whole number) of the path? (Take $п=\frac{22}{7}$)
Answer & explanation
Correct answer: option 3
We know that,
Circumference of a circle = 2πR
Area of a circle = πR2
Where R = radius of the circle
Let the inner radius be r.
Now,
2πr = 264
= r = 264 × \(\frac{7}{22}\) × \(\frac{1}{2}\)
= r = 42
So, the outer radius of circular path = 42 + 3 = 45 m
Now, the area of the circular path = π (452 - 422)
= \(\frac{22}{7}\) × 261 = 820 m2