The inner circumference of a circular path enclosed between two concentric circles is 264 m. The uniform width of the circular path is 3 m. What is the area (in m², to the nearest whole number) of the path? (Take $п=\frac{22}{7}$)

820

We know that,

Circumference of a circle = 2πR

Area of a circle = πR²

Where R = radius of the circle

Let the inner radius be r.

Now,

2πr = 264

= r = 264 × \(\frac{7}{22}\) × \(\frac{1}{2}\)

= r = 42

So, the outer radius of circular path = 42 + 3 = 45 m

Now, the area of the circular path = π (45² - 42²)

= \(\frac{22}{7}\) × 261 = 820 m²