Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The ratio of the speed of the electron in the first Bohr orbit of hydrogen and the speed of light is equal to (where e, h and c have their usual meanings)

Options:

$2 \pi h c / e^2$

$e^2 h / 2 \pi c$

$e^2 c / 2 \pi h$

$2 \pi e^2 / h c$

Correct Answer:

$2 \pi e^2 / h c$

Explanation:

Speed of electron in nth orbit (in CGS) $v_n=\frac{2 \pi Z e^2}{n h}(k=1)$

For first orbit H2 ; n = 1 and Z = 1

So $v=\frac{2 \pi e^2}{h} \Rightarrow \frac{v}{c}=\frac{2 \pi e^2}{h c}$