Practicing Success
The IUPAC name for \(K_2[Cr(CN)_2O_2(O_2)NH_3]\) is
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potassium amminedicyanodioxoperoxochromate (VI) potassium amminedicyanotetroxochromium (III) potassium amminedicyanochromate (IV) potassium amminocyanodiperoxochromate (VI) |
potassium amminedicyanodioxoperoxochromate (VI) |
The correct answer is option 1. potassium amminedicyanodioxoperoxochromate (VI). Here, the given compound is \(K_2[Cr(CN)_2O_2(O_2)NH_3]\) Let us first find the oxidation number of the central metal ion, i.e., \(Cr\) Here the given ligands are:
Let the Oxidation number of \(Cr\) be \(x\) \(∴ 2(1) + x + 2(-1) + 2(-2) + 1(-2) + 1(0) = 0\) \(⇒ 2 + x -2 - 4 -2 + 0 = 0\) \(⇒ x - 6 = 0\) \(⇒ x = 6\) Thus the name of the complex will be: \(\text{Potassium amminedicyanodioxoperoxo chromate(VI)}\) |