The IUPAC name for K_2[Cr(CN)_2O_2(O_2)NH_3] is

The correct answer is option 1. potassium amminedicyanodioxoperoxochromate (VI).

Here, the given compound is \(K_2[Cr(CN)_2O_2(O_2)NH_3]\)

Let us first find the oxidation number of the central metal ion, i.e., \(Cr\)

Here the given ligands are:

Ligand	Name	Charge
\(CN\)	cyano	\(-1\)
\(O^{2-}\)	oxo	\(-2\)
\(O_2^{2-}\)	peroxo	\(-2\)
\(NH_3\)	ammine	\(0\)

Let the Oxidation number of \(Cr\) be \(x\)

\(∴ 2(1) + x + 2(-1) + 2(-2) + 1(-2) + 1(0) = 0\)

\(⇒ 2 + x -2 - 4 -2 + 0 = 0\)

\(⇒ x - 6 = 0\)

\(⇒ x = 6\)

 Thus the name of the complex will be: \(\text{Potassium amminedicyanodioxoperoxo chromate(VI)}\)