Evaluate ∫ √(2ax - x^2) dx.

The correct answer is Option (3) → $\frac{x - a}{2} \sqrt{a^2 - (x - a)^2} + \frac{a^2}{2} \sin^{-1} \frac{x - a}{a} + C$

Let, $I = \int \sqrt{2ax - x^2} dx$

$= \int \sqrt{a^2 - a^2 + 2ax - x^2} \cdot dx$

$= \int \sqrt{a^2 - (x^2 - 2ax + a^2)} \cdot dx$

$= \int \sqrt{a^2 - (x - a)^2} \cdot dx \text{}$

Put $x - a = t \Rightarrow dx = dt$

$= \int \sqrt{a^2 - t^2} \cdot dt$

$= \frac{t}{2} \sqrt{a^2 - t^2} + \frac{a^2}{2} \sin^{-1} \frac{t}{a} + C$

$= \frac{x - a}{2} \sqrt{a^2 - (x - a)^2} + \frac{a^2}{2} \sin^{-1} \frac{x - a}{a} + C \text{}$