The value of $Δ=\begin{vmatrix}b-c&c-a&a-b\\c-a&a-b&b-c\\a-b &b-c &c-a\end{vmatrix}$ is
Answer & explanation
Correct answer: option 2
$Δ=\begin{vmatrix}b-c&c-a&a-b\\c-a&a-b&b-c\\a-b &b-c &c-a\end{vmatrix}$
$C_1→C_1+C_2 + C_3$
$Δ=\begin{vmatrix}0&c-a&a-b\\0&a-b&b-c\\0 &b-c &c-a\end{vmatrix}=0$