Practicing Success
Simplify : $3p - [3p - \overline{p+q} - \begin{Bmatrix}3p-(p-\overline{q-p})\end{Bmatrix}]$ |
3p - q p + 2q 3p + 2q 2p + 2q |
2p + 2q |
Given = $3p - [3p - \overline{p+q} - \begin{Bmatrix}3p-(p-\overline{q-p})\end{Bmatrix}]$ Solving above equation, 3p - [3p - p - q - {3p - (p - q + p)}] = 3p - [3p - p - q - {3p - (2p - q)}] = 3p - [3p - p - q - {3p - 2p + q}] = 3p - [3p - p - q - {p + q}] = 3p - [3p - p - q - p - q] = 3p - [p - 2q] = 3p - p + 2q = 2p + 2q |