From a solid cylinder whose height is 2.4 cm and diameter is 1.4 cm, a conical cavity of same height and same diameter is carved out. The total surface area of the remaining solid is : (Use $\pi=\frac{22}{7}$)

$17.6 ~cm^2$

Curved surface area of cylindrical part

Remaining surface area of solid = Curved surface area of cylindrical part + Curved surface area of conical part + Area of circular base

= 2πrh + πrl + πr²

= 2 × \(\frac{22}{7}\) × 0.7 × 2.4 + \(\frac{22}{7}\) ×  0.7 × 2.5 +  \(\frac{22}{7}\) ×
( 0.7) ²

= \(\frac{22}{7}\) × 0.7 ( 2 × 2.4 + 2.5 + 0.7 )

= \(\frac{11}{5}\) × ( 8 )

= \(\frac{88}{5}\)

= 17.6

The correct answer is Option (2) → $17.6 ~cm^2$