The present ages of A and B are in the ratio 3 : 4. Twelve years ago, their ages were in the ratio 2 : 3. The sum of the present ages of A and B (in years) is:

84

ATQ,

Lets assume present age of A and B are 3x and 4x respectively.

Given \(\frac{3x - 12}{4x - 12}\) = \(\frac{2}{3}\)

⇒ 9x - 36 = 8x - 24

⇒ x = 12

Present age of A = 36

Present age of B = 48

Sum of ages of A and B = 84 years