Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Moving Charges and Magnetism

Question:

Which of the following is the correct expression for force due to a magnetic field $(\vec{B})$ on a straight conductor of length $(l)$ carrying current I?

Options:

$\vec{F}=I(\vec{B} \times \vec{l})$

$\vec{F}=\vec{B}(\vec{I} \times \vec{l})$

$\vec{F}=I(\vec{l} \times \vec{B})$

$\vec{F}=l(\vec{I} \times \vec{B})$

Correct Answer:

$\vec{F}=I(\vec{l} \times \vec{B})$

Explanation:

The correct answer is Option (3) → $\vec{F}=I(\vec{l} \times \vec{B})$