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In terms of Bohr radius $a_o$ the radius of 2nd Bohr orbit of Hydrogen is : |
$4 a_o$ $8 a_o$ $\sqrt{2} a_o$ $2 a_o$ |
$4 a_o$ |
The correct answer is Option (1) → $4 a_o$ The radius of the n-th Bohr orbit for the hydrogen atom is - $r_n=a_0.n^2$ where, $r_n$ = n-th Bohr obit radius n = Principle quantum number $r_1=a_0.(2)^2=4a_0$ |
