One mole of a diatomic gas undergoes a process :
\(P = \frac{P_o}{1 + (\frac{V}{V_o})^3}\)
where Po and Vo are constants. The translational kinetic energy of the gas when V = Vo is given by :
Answer & explanation
Correct answer: option 2
\(P = \frac{P_o}{1 + (\frac{V}{V_o})^3 } = \frac{P_o}{2}\)
\(T = \frac{P_o V_o}{2R}\)
Therefore translational kinetic energy is equal to :
\(\frac{3}{2}RT = \frac{3R}{2} \frac{P_o V_o}{2R}\)
\(\frac{3}{2}RT = \frac{3P_o V_o}{4}\)