Find the adjoint of the matrix $A =\begin{bmatrix}1&1&1\\2&1&-3\\-1&2&3\end{bmatrix}$.
Answer & explanation
Correct answer: option 1
Let $C_{ij}$ be a cofactor of $a_{ij}$ in A. Then, the cofactors of elements of A are given by
$C_{11}=\begin{vmatrix}1&-3\\2&3\end{vmatrix}=9$
$C_{12}=-\begin{vmatrix}2&-3\\-1&3\end{vmatrix}=-3$
$C_{13}=\begin{vmatrix}2&1\\-1&2\end{vmatrix}=5$
$C_{21}=-\begin{vmatrix}1&1\\2&3\end{vmatrix}=-1$
$C_{22}=\begin{vmatrix}1&1\\-1&3\end{vmatrix}=4$
$C_{23}=-\begin{vmatrix}1&1\\-12&2\end{vmatrix}=-3$
$C_{31}=\begin{vmatrix}1&1\\-1&-3\end{vmatrix}=-4$
$C_{31}=-\begin{vmatrix}1&1\\2&-3\end{vmatrix}=5$
$C_{31}=\begin{vmatrix}1&1\\2&1\end{vmatrix}=-1$
$∴adj\,A=\begin{bmatrix}9&-3&5\\-1&4&-3\\-4&5&-1\end{bmatrix}^T=\begin{bmatrix}9&-1&-4\\-3&4&5\\5&-3&-1\end{bmatrix}$