How does refractive index ($\mu$) of a material vary with respect to wavelength (l$\lambda$) ? A and B are constants
Answer & explanation
Correct answer: option 2
$\text{Cauchy relation } \mu = A + \frac{B}{\lambda^2}$
How does refractive index ($\mu$) of a material vary with respect to wavelength (l$\lambda$) ? A and B are constants
Correct answer: option 2
$\text{Cauchy relation } \mu = A + \frac{B}{\lambda^2}$