Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Ray Optics

Question:

How does refractive index ($\mu$) of a material vary with respect to wavelength (l$\lambda$) ? A and B are constants

Options:

$\mu = A + B\lambda^2$

$\mu = A + \frac{B}{\lambda^2}$

$\mu = A + B\lambda$

$\mu = A + \frac{B}{\lambda}$

Correct Answer:

$\mu = A + \frac{B}{\lambda^2}$

Explanation:

$\text{Cauchy relation } \mu = A + \frac{B}{\lambda^2}$