In a certain code language, IMPUDENT is written as PFXMHAWK. How will ABNORMAL be written in that language?

EXRKPOOX

1   2    3    4   5    6   7     8    9  10  11  12  13

 A   B   C    D   E    F   G    H    I    J    K    L   M

 ↓    ↓    ↓    ↓    ↓     ↓   ↓    ↓     ↓   ↓    ↓    ↓    ↓

 Z   Y    X   W   V    U   T    S    R   Q   P    O   N

26  25  24  23  22  21  20  19  18  17  16  15  14

****************************************************

The logic followed here is;

--> The first letter is subtracted by 3 and shifted to the second position and the second letter add by 3 and shifted to the first position.

--> Third letter is subtracted by 3 and shifted to the 4th position and 4th letter adds by 3 and shifted to the 3rd position 

--> The last 2 letters are interchanged and decrease or increased by 3

That's how IMPUDENT is written as PFXMHAWK

Thus,  ABNORMAL be written as EXRKPOOX