A sum of Rs. 5000 is divided into two parts such that the simple interest on the first part for \(4\frac{1 }{5}\) years at \(6\frac{2 }{3}\)% p.a. is double the simple interest on the second part for \(2\frac{3 }{4}\) years at 4% p.a. Find is the difference between the two parts.

600

P₁ x \(\frac{20}{3}\) x \(\frac{21}{5}\)  =  2 x P₂ x 4% x \(\frac{11}{4}\)

P₁ x  28          =   P₂ x 22

⇒ P₁ : P₂ = 11 : 14

⇒ Total = 25R = 5000

⇒ R = 200

Difference = 3R = 600