If sin θ + cos θ = $\sqrt{2}$, then find the value of cosec θ + cot ?
Answer & explanation
Correct answer: option 4
sin θ + cos θ = \(\sqrt { 2}\)
Put θ = 45º
sin 45º + cos 45º = \(\sqrt { 2}\)
\(\frac{1}{√2}\) + \(\frac{1}{√2}\) = \(\sqrt { 2}\)
\(\frac{2}{√2}\) = \(\sqrt { 2}\)
\(\sqrt { 2}\) = \(\sqrt { 2}\)
LHS = RHS ( satisfied )
Now,
( cosec θ + cotθ )
= ( cosec 45º + cot 45º )
= \(\sqrt { 2}\) + 1