If $y=logx^5$, then $\frac{d^2y}{dx^2}$ is given by :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $-\frac{5}{x^2}$
$y=\log x^5=5\log x$
so $\frac{dy}{dx}=\frac{5}{x}$
so $\frac{d^2y}{dx^2}=-\frac{5}{x^2}$
If $y=logx^5$, then $\frac{d^2y}{dx^2}$ is given by :
Correct answer: option 4
The correct answer is Option (4) → $-\frac{5}{x^2}$
$y=\log x^5=5\log x$
so $\frac{dy}{dx}=\frac{5}{x}$
so $\frac{d^2y}{dx^2}=-\frac{5}{x^2}$