The emfs and resistances in the given circuit have the following values. $E_1=4.2 ~V, E_2=1.9 ~V$ $r_1=2.0 \Omega, r_2=1.6 \Omega, R=6.0 \Omega$ What is the current in the circuit?

383 mA 635 mA 240 mA 958 mA

240 mA

Applying Kirchoff's Lawin the circuit  $ E_1 - E_2 -I( R + r_1 + r_2) = 0$ $ I = \frac{E_1-E_2}{R + r_1 + r_2} = \frac{4.2 - 1.9}{6+2+1.6} =\frac{2.3}{9.6} = 240mA$