Practicing Success
If $(2x - 5y)^3 - (2x + 5y)^3 = y[Ax^2 + By^2]$, then what is the value of $(2A - B)$? |
25 40 15 10 |
10 |
a3 – b3 = (a – b) (a2 + b2 + ab) (2x – 5x)3 – (2x + 5y)3 = y[Ax2 + By2] = [(2x – 5y) – (2x + 5y)] [(2x – 5y)2 + (2x + 5y)2 + (2x – 5y)(2x + 5y)] = y[Ax2 + By2] = [2x – 5y – 2x – 5y][4x2 + 25y2 – 20xy + 4x2 + 25y2 + 20xy + 4x2 – 25y2] = y[Ax2 + By2] = [ – 10y] [12x2 + 25y2] = y[Ax2 + By2] = y [ – 120x2 – 250y2] = y[Ax2 + By2] On comparing = A = – 120 and B = – 250 Now, = (2A – B) = [2 × ( – 120)] – ( – 250) = – 240 + 250 = 10 |