Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

The Figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet of move from C to D and t2 is the time to move from A to B then:

Options:

t1 = 4t

t1 = 2t 2

t1 = t

t1 > t2

Correct Answer:

t1 = 2t 2

Explanation:

Areal velocity of a particle moving in a planetary motion is constant.

Velocity for area SCD : A1 / t1 ; Velocity for area SAB : A2 / t2

\(\Rightarrow \frac{A_1}{t_1} = \frac{A_2}{t_2}\)

It is given that $ A_1 = 2A_2$

\(\Rightarrow t_1 = 2t_2\)