The Figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet of move from C to D and t2 is the time to move from A to B then:
Answer & explanation
Correct answer: option 2
Areal velocity of a particle moving in a planetary motion is constant.
Velocity for area SCD : A1 / t1 ; Velocity for area SAB : A2 / t2
\(\Rightarrow \frac{A_1}{t_1} = \frac{A_2}{t_2}\)
It is given that $ A_1 = 2A_2$
\(\Rightarrow t_1 = 2t_2\)