The side of a rhombus is 5 cm and one of its diagonal is 8 cm. What is the area of the rhombus?
Answer & explanation
Correct answer: option 2
In rhombus diagonals bisect each other at right angle.
Therefore, OD = \(\frac{1}{2}\) DB = \(\frac{1}{2}\) × 8 = 4
Now, In Δ AOD;
⇒ OA2 = AD2 - OD2
⇒ OA2 = 52 - 42 = 25 - 16 = 9
⇒ OA = 3 cm
⇒ AC = 6 cm
⇒ Area of rhombus = \(\frac{1}{2}\) AC × BD = \(\frac{1}{2}\) 8 × 6 = 24 cm2