Let f(2) = 4 and f'(2) = 4. Then $\under

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

Let f(2) = 4 and f'(2) = 4. Then $\underset{x→2}{\lim}\frac{xf(2)-2f(x)}{x-2}$ is given by

Options:

-2

-4

Correct Answer:

-4

Explanation:

$\underset{x→2}{\lim}\frac{xf(2)-2f(x)}{x-2}=\underset{x→2}{\lim}\frac{f(2)-2f'(x)}{1}=f(2)-2f'(2)=4-2.4=-4$