Let f(2) = 4 and f'(2) = 4. Then $\underset{x→2}{\lim}\frac{xf(2)-2f(x)}{x-2}$ is given by
Answer & explanation
Correct answer: option 3
$\underset{x→2}{\lim}\frac{xf(2)-2f(x)}{x-2}=\underset{x→2}{\lim}\frac{f(2)-2f'(x)}{1}=f(2)-2f'(2)=4-2.4=-4$
Let f(2) = 4 and f'(2) = 4. Then $\underset{x→2}{\lim}\frac{xf(2)-2f(x)}{x-2}$ is given by
Correct answer: option 3
$\underset{x→2}{\lim}\frac{xf(2)-2f(x)}{x-2}=\underset{x→2}{\lim}\frac{f(2)-2f'(x)}{1}=f(2)-2f'(2)=4-2.4=-4$