If A is an involuntary matrix given by $A=\begin{bmatrix}0&1&-1\\4&-3&4\\3&-3&4\end{bmatrix}$, then the inverse of $\frac{1}{2}A$ will be
Answer & explanation
Correct answer: option 1
It is given that A is an involutory matrix.
$∴A^2=I$
$⇒AA=I⇒(\frac{1}{2}A)(2A)=I⇒(\frac{1}{2}A)^{-1}=(2A)$