Practicing Success
Practicing Success
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If A is an involuntary matrix given by $A=\begin{bmatrix}0&1&-1\\4&-3&4\\3&-3&4\end{bmatrix}$, then the inverse of $\frac{1}{2}A$ will be |
$2A$ $\frac{1}{2}A^{-1}$ $\frac{1}{2}A$ $A^2$ |
$2A$ |
It is given that A is an involutory matrix. $∴A^2=I$ $⇒AA=I⇒(\frac{1}{2}A)(2A)=I⇒(\frac{1}{2}A)^{-1}=(2A)$ |
