Practicing Success
If a (a + b + c)2 = 1792 b (a + b + c)2 = 1536 c (a + b + c)2 = 768, then, find the value of b2 + 11. |
36 6 47 75 |
47 |
Add all the equations. (a + b + c) (a + b + c)2 = 1792 + 1536 + 768 = 4096 (a + b + c)3 = 4096 a + b + c = \(\sqrt[3]{4096}\) a + b + c = 16 Now, b (a + b + c)2 = 1536 b (16)2 = 1536 b = \(\frac{1536}{256}\) = 6 ⇒ b2 + 11 = 62 + 11 = 47 |