Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Probability

Question:

If random variable X has the following probability distribution:

X: 0 1 2 3 4 5 6 7 8
P(X=x): a 3a 5a 7a 9a 11a 13a 15a 17a

then the value of a is

Options:

$\frac{7}{81}$

$\frac{5}{81}$

$\frac{2}{81}$

$\frac{1}{81}$

Correct Answer:

$\frac{1}{81}$

Explanation:

The given distribution is the probability distribution.

$∴ \sum\limits^{8}_{r=0}P(X=r)=1$

$⇒ a +3a + 5a +7a + 9a + 11a + 13 a + 15a + 17a = 1$

$⇒ a =\frac{1}{81}$