The greatest number of six digits which gives remainder 10 when divided by 48, 60, 54 and 90 is?
Answer & explanation
Correct answer: option 1
48, 60, 54, 90 → LCM = 2160
2160 × K + 10
2160 × K = 999999 - 10
2160 × K = 999989
= 999999 - 2069 = 997930