If the equation of a line is $x = ay + b, z = cy + d$, then find the direction ratios of the line and a point on the line. |
Direction Ratios: $(a, 1, c)$; Point: $(b, 0, d)$ Direction Ratios: $(1, a, c)$; Point: $(0, b, d)$ Direction Ratios: $(a, b, c)$; Point: $(1, 0, 1)$ Direction Ratios: $(b, 1, d)$; Point: $(a, 0, c)$ |
Direction Ratios: $(a, 1, c)$; Point: $(b, 0, d)$ |
The correct answer is Option (1) → Direction Ratios: $(a, 1, c)$; Point: $(b, 0, d)$ ## $x = ay + b ⇒\frac{x - b}{a} = y$ $z = cy + d ⇒\frac{z - d}{c} = y$ $∴$ Equation of the line: $\frac{x - b}{a} = \frac{y - 0}{1} = \frac{z - d}{c}$ $\textbf{Direction ratios of the line}: (a, 1, c)$ $\textbf{Point on the line}:(b, 0, d)$ |