If sin θ = 11/15, then the value of (sec θ - tan θ) is :

sin θ  = \(\frac{11}{15}\)

{ sin θ = \(\frac{P}{H}\) }

By using pythagoras theorem ,

P² + B² = H²

11² + B² = 15²

B² = 225 - 121

B = 2√26

Now,

secθ - tanθ

= \(\frac{H}{B}\) - \(\frac{P}{B}\)

= \(\frac{15}{2√26 }\) - \(\frac{11}{2√26 }\)

= \(\frac{4}{2√26 }\)

= \(\frac{√26}{13 }\)