Practicing Success
Practicing Success
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If A and B are two independent events with $P(A) = \frac{3}{5}$ and $P(B) = \frac{4}{9}$, then P(A' ∩ B') is equal to |
$\frac{4}{15}$ $\frac{8}{45}$ $\frac{1}{3}$ $\frac{2}{9}$ |
$\frac{2}{9}$ |
$P(B) = \frac{4}{9}$ A, B → independent ⇒ A', B' → also independent So P(A' ∩ B') = P(A') P(B') = (1 - P(A)) (1 - P(B)) = $(1-\frac{3}{5})(1-\frac{4}{9})$ = $\frac{2}{3} × \frac{5}{9}$ = $\frac{2}{9}$ |
