A man on tour travels the first 360 km by train at 72 km/h, the next 160 km on a motorcycle at 12.80 km/h, and the last 200 km by bicycle at 16 km/h. Ignoring the buffer times between the different modes of travel, what is the average speed (in m/s)for his tour?

6.67

Average Speed = \(\frac{Total \;Distance}{Total \;Time}\)

Distance = Speed × Time

Time= \(\frac{Distance}{Speed}\)

T1 = \(\frac{360}{72}\) = 5 hours hours

T2 = \(\frac{160}{12.80}\) = 12 .5 hours

T3 = \(\frac{200}{16}\) = 12.5 hours

Total distance = 360 + 160 +200 = 720 km

Total time = 5+ 12.5 + 12.5 = 30 hours

Average speed = \(\frac{720  }{30}\) = 24 km/h

So , Average speed is 24 km/h

24 × \(\frac{5}{18}\) = 6.67 m/sec